# SOLUTION: I am so lost with this, I don't even understand where to begin. We are supose to find each value of x. Here is the problem log2 8=x The 2 is supose to be small and at the

Algebra ->  Algebra  -> Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I am so lost with this, I don't even understand where to begin. We are supose to find each value of x. Here is the problem log2 8=x The 2 is supose to be small and at the       Log On

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 Algebra: Logarithm Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on logarithm Question 34221This question is from textbook Intermediate Algebra : I am so lost with this, I don't even understand where to begin. We are supose to find each value of x. Here is the problem log2 8=x The 2 is supose to be small and at the bottom of the g. Can someone please help me?This question is from textbook Intermediate Algebra Answer by venugopalramana(3286)   (Show Source): You can put this solution on YOUR website!THIS MEANS LOG (8) TO BASE 2 =X...WHICH MEANS 2^X=8...WE HAVE TO FIND X ...WE SEE THAT 8=2*2*2=2^3 2^X=2^3...OR....X=3 IN GENERAL IF ....B^P=N...WE SAY LOG OF N TO BASE B =P...WRITTEN AS LOG(N)TO BASE B=P