SOLUTION: Ok, I'd like to say thank you in advance. The problem is: log(base 2)(3x-1)is less than or equal to(<) 4. please help.

SOLUTION: Ok, I'd like to say thank you in advance. The problem is: log(base 2)(3x-1)is less than or equal to(<) 4. please help.

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Question 337928: Ok, I'd like to say thank you in advance. The problem is: log(base 2)(3x-1)is less than or equal to(<) 4. please help.
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
log[2](3x-1)<=4
2^(log[2](3x-1))<=2^4
3x-1<=16
3x<=17
x<=17/3
3x-1>0 Log<=0 is not allowed.
3x>1
x>1/3
.

.
Ed
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