SOLUTION: [e^(2x)] − [2e^(x)]−(8) =0

Algebra.Com
Question 334536: [e^(2x)] − [2e^(x)]−(8) =0
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Hint: Let . This will mean that


So the given equation then becomes . Solve for z and then use those solutions to find the solutions in terms of x.

RELATED QUESTIONS

Solve the logarithmic or exponential equation. 1.(525)/(1+e^-x)=275 2.ln(x +1) − (answered by solver91311)
solve for x e^2x - 2e^x - 8 =... (answered by lwsshak3)
− x − 8 (answered by ikleyn)
(e^2x)-(2e^x)-15=0 (answered by lwsshak3)
e^(2x)-2e^x+1 =0... (answered by lwsshak3)
solve: {{{e^(2x) - 2e^x... (answered by nerdybill)
Solve using substitution: -y − 5x = -7 2y − 2x = 14 Solve using... (answered by Alan3354)
(a) 3^(2x) = 5 (b) 2e^(x−1) = 7 (c) 5^(1−x) =... (answered by Alan3354)
Simplify the expression. 5(x − 1) − 3(x2 + 2x + 3) − 8(x +... (answered by MathLover1)