SOLUTION: log(10x/y)=1+log x-log y. I have no idea whether this problem is true or false. Could you please help show me the steps in finding the answer?

Question 33366: log(10x/y)=1+log x-log y. I have no idea whether this problem is true or false. Could you please help show me the steps in finding the answer?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
You need to know the Laws of logarithms.
log(10x/y)= log(10x)-logy
=log10+logx-logy
=1+logx-logy
Cheers,
Stan H.
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