SOLUTION: Solve where appropriate
log2 square root x^2-4=1
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Question 328531: Solve where appropriate
log2 square root x^2-4=1
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve where appropriate
log2 (square root x^2-4) = 1
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sqrt(x^2-4) = 2^1
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Square both sides:
x^2-4 = 2
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x^2 = 6
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x = sqrt(6) or x = -sqrt(6)
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Cheers,
Stan H.
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