SOLUTION: Solve where appropriate 43=4e^3x

Question 328530: Solve where appropriate
43=4e^3x
Found 2 solutions by nyc_function, Alan3354:
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
Isolate the exponential expression by dividing both sides by 4.
43 = 4e^(3x)
43/4 = e^(3x)
Now take the natural log of both sides of the equation.
Let ln = natural log
ln(43/4) = ln[e^(3x)]
ln(43/4) = 3xlne
We now solve for x. To do so, divide both sides by lne.
ln(43/4) divided by lne = x
NOTE: lne = 1 by definition
ln(43/4) divided by 1 = x
ln(43/4) = x
2.374905755 = x
Round to the nearest tenths.
So, x is approximately 2.4

Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
43=4e^3x
e^3x = 43/4 = 10.75
3x = ln(10.75)
x = ln(10.75)/3

RELATED QUESTIONS
Solve... (answered by Alan3354)
2e^(3x)=4e^(5x), solve for... (answered by josgarithmetic)
Solve where appropriate log2 square root... (answered by stanbon)
Solve each system using substition. Write no solution or infinitely many solutions where... (answered by stanbon)
How do you solve each system by graphing? Write no solution or infinitely many solutions... (answered by stanbon)
solve for x:... (answered by MathLover1)
for 2e^(3x)=4e^(5x) solve for x using... (answered by solver91311)
Solve for x using logs.... (answered by nerdybill)
How do I solve (4e^-2)^3x? I'm so confused. (answered by tommyt3rd)