SOLUTION: Need Help Please! I am failing this class.. 5. Solve. Where appropriate, include approximations to the nearest thousandth. If no solution exists, state this. logx (log3 9) =

Question 328052: Need Help Please!
I am failing this class..
5. Solve. Where appropriate, include approximations to the nearest thousandth. If no solution exists, state this.
logx (log3 9) = 2
Found 2 solutions by rapaljer, josmiceli:
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
First calculate by converting to exponential notation: , so

Now, you need to find

You need to solve for x in this equation:

Translate to exponential notation:
, so , which is approximately 1.414.

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Seminole State College of Florida
Altamonte Springs Campus

Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Wow, this looks so confusing, I'm not sure what it says.
The is where to start, since it looks simple.
It says "I am an exponent to the base that gives
I know that , so

Now I have

This is saying "An exponent which is , with a base that is
gives me
I'll rewrite it as:

Now take the square root of both sides
answer
and
not answer
Only the positive result would work here, because what would the
answer to this be?

Can't solve it
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