SOLUTION: Need Help Please! Failing this class... Solve. Where appropriate, include approximations to the nearest thousandth. If no solution exists, state this. log9x = 1/2 I bel

SOLUTION: Need Help Please! Failing this class... Solve. Where appropriate, include approximations to the nearest thousandth. If no solution exists, state this. log9x = 1/2 I bel

Algebra.Com

Question 328050: Need Help Please! Failing this class...

Solve. Where appropriate, include approximations to the nearest thousandth. If no solution exists, state this.
log9x = 1/2
I believe 9 is the base.
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
log(base 9)of x = 1/2 is the same thing as 9^(1/2) = x.
Now, 9^(1/2) = sqrt{9}, where sqrt = square root for short.
Then sqrt{9} = x
3 = x
The value of x is 3.

RELATED QUESTIONS
Need Help Please! I am failing this class.. 5. Solve. Where appropriate, include... (answered by rapaljer,josmiceli)

Need help please! I am failing this class and just can't seem to grasp it.. Solve. Where (answered by josmiceli)

Solve. Where appropriate, include approximations to the nearest thousandth. If no... (answered by edjones)

Solve. Where appropriate, include approximations to the nearest thousandth. If no... (answered by edjones)

solve. where appropriate, include approximations to the nearest thousandth. if no... (answered by solver91311)

Solve. Where appropriate, include approximations to the nearest thousandth. If no... (answered by jsmallt9)

solve. where appropriate, include approximations to the nearest thousandth. if no... (answered by josmiceli,malaydassharma,nerdybill)

solve. where appropriate, include approximations to the nearest thousandth. if no... (answered by nerdybill)

solve. where appropriate, include approximations to the nearest thousandth. If no... (answered by Fombitz)