# SOLUTION: I can not figure out the last steps on how the answer is attain Please help show each step also how to enter it in the calculator for graphing solution. 3^(2x+2) =7^X ln (3^2x

Algebra ->  Algebra  -> Logarithm Solvers, Trainers and Word Problems -> SOLUTION: I can not figure out the last steps on how the answer is attain Please help show each step also how to enter it in the calculator for graphing solution. 3^(2x+2) =7^X ln (3^2x      Log On

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 Question 32728: I can not figure out the last steps on how the answer is attain Please help show each step also how to enter it in the calculator for graphing solution. 3^(2x+2) =7^X ln (3^2x+2) ==ln 7^x (2x+2) ln (3) = x ln(7) 2x ln (3)= x ln 7-2 ln 3 2x ln (30-x(7)==-2 ln(3) x(2 ln 3-ln 7) = -2 ln (3) x= Now I am stuck how do I finish it???? How is it enter into the calculator. Must know for my math class. Any help, very appreciated. thanks, JodyAnswer by mukhopadhyay(490)   (Show Source): You can put this solution on YOUR website!3^(2x+2) = 7^X ln (3^2x+2) =ln 7^x (2x+2) ln (3) = x ln(7) 2x ln (3)-x ln 7 = -2 ln 3 x[2 ln (3) - ln (7)] = -2 ln(3) x = [2 ln (3) - ln (7) ]/ [-2 ln(3)] x= ln (7)/[2 ln (3)] - 1