SOLUTION: Please help me to solve.
e^(4-5x)=988
Thank you!
Algebra.Com
Question 326240: Please help me to solve.
e^(4-5x)=988
Thank you!
Found 2 solutions by stanbon, solver91311:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
e^(4-5x)=988
-----
Take the natural log of both sides to get:
(4-5x) = ln(988)
4-5x = 6.8957
-5x = 2.8957
x = -0.5791
===============
Cheers,
Stan H.
===============
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Take the natural log of both sides:
\ =\ \ln(989))
Use:
\ =\ n\log_b(x))
\ln\left(e\right)\ =\ \ln(989))
Then use:
\ =\ 1)
)
)
is just a constant, so solve like any other linear equation in 
John
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