SOLUTION: log6(b2 + 2) + log62 = 2

SOLUTION: log6(b2 + 2) + log62 = 2

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Question 32455: log6(b2 + 2) + log62 = 2

Answer by mukhopadhyay(490) (Show Source): You can put this solution on YOUR website!
log6(b^2 + 2) + log62 = 2
=>log(base6)2(b^2+2) = 2
=>2(b^2+2)=36
=> b^2+2 = 18
=> b^2 = 16
=> b=4 or b=-4
Answer: b=4 or b=-4
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