SOLUTION: how do you find a logarithm set say the question is
7^4x-13=343?
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Question 313485: how do you find a logarithm set say the question is
7^4x-13=343?
Found 2 solutions by nyc_function, nerdybill:
Answer by nyc_function(2741) (Show Source): You can put this solution on YOUR website!
Are you looking for x?
If so, 434 = 7^3.
7^(4x - 13) = 7^(3)
Since we now have the same base 7 on both sides, bring down and equate all exponents.
4x - 13 = 3
4x = 3 + 13
4x = 16
x = 16/4
x = 4
Is this what you need?
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
I think you mean:
If not, please write back...
.
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