SOLUTION: log2/log3.log3/log4.log4/log5.........log15/log16
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Question 312070: log2/log3.log3/log4.log4/log5.........log15/log16
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
What does this mean? Are you trying to multiply a series of factors each consisting of some log divided by some other log?
John
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