SOLUTION: I need help solving this: Log4X-Log4(X-4)=1 the first two 4's are the bases. I tried distributing the second log by writing it like this: log4X-log4X-log4(4)=1 and then I

Algebra.Com
Question 309224: I need help solving this:
Log4X-Log4(X-4)=1
the first two 4's are the bases.
I tried distributing the second log by writing it like this:
log4X-log4X-log4(4)=1
and then I canceled out the first two and was left with -log4(4)=1 and I have no idea what I'm doing past that or even if that's right.

Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
Log4X-Log4(X-4)=1
the first two 4's are the bases.
------------


x/(x-4) = 4
x = 4(x-4)
x = 4x-16
3x = 16
x = 16/3


RELATED QUESTIONS

please please help me on this question: solve for s, p= 3(s+100)/4 I tried... (answered by stanbon)
I need help solving this I have tried it for about 20 mins now! Log... (answered by Alan3354)
if you cant find the book then the question is log2 (x+1)-log4 x=1 i am... (answered by jsmallt9,RAY100)
I have this exponential equation that I cannot seem to solve: 5^x = 4^x+1 I didn't... (answered by greenestamps,ikleyn)
I have tried this with my son 4 times...could you please help!... (answered by stanbon)
I have one last question on my homework and I can’t seem to figure it out. I’ll send the (answered by greenestamps,Theo,apshu)
i need help solving this and the steps logx-1=-log(x-9) and also... (answered by lwsshak3)
-3(-x+4) = 3x-12 I tried distributing the first expression: 3x - 12 = 3x - 12... (answered by scott8148)
I need help factoring this expression (x+5)^2(x+y-2) I tried using the foil method on (answered by Alan3354)