SOLUTION: Solve 2log4-log3+2logx-4=0. a. 12.3308 b. 43.3013 c. 86.6025 d. 1875

Question 309126: Solve 2log4-log3+2logx-4=0.
a. 12.3308
b. 43.3013
c. 86.6025
d. 1875
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve 2log4-log3+2log(x-4)=0.
----
log(16)-log(3) + log(x)^2 = 4
log(16/3)(x)^2) = 4
---
(16/3)x^2 = 10^4
x^2 = (3/16)10^4
---
x = (100/4)sqrt(3)
x = 25*sqrt(3)
x = 43.3013
=================
Cheers,
Stan H.
=================

a. 12.3308
b. 43.3013
c. 86.6025
d. 1875

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