SOLUTION: Evaluate the logarithmic function for three values of x between zero and one, three values of x greater tha? Evaluate the logarithmic function for three values of x between zero a

Question 303174: Evaluate the logarithmic function for three values of x between zero and one, three values of x greater tha?
Evaluate the logarithmic function for three values of x between zero and one, three values of x greater than 1, and at x=1

g(x) = ln(x + 2)

Answer by CharlesG2(834) (Show Source): You can put this solution on YOUR website!
Evaluate the logarithmic function for three values of x between zero and one, three values of x greater tha?
Evaluate the logarithmic function for three values of x between zero and one, three values of x greater than 1, and at x=1
g(x) = ln(x + 2)
Am guessing that "Evaluate the logarithmic function for three values of x between zero and one, three values of x greater tha?" is a mistake.
So evaluating "Evaluate the logarithmic function for three values of x between zero and one, three values of x greater than 1, and at x=1" instead.
g(0) = ln(0 + 2) = ln 2
g(0.25) = ln(0.25 + 2) = ln(2.25) = ln(9/4) = ln 9 - ln 4
(by logarithmic division rule)
g(0.5) = ln(0.5 + 2) = ln(2.5) = ln(5/2) = ln 5 - ln 2
g(0.75) = ln(0.75 + 2) = ln(2.75) = ln(11/4) = ln 11 - ln 4
g(1) = ln(1 + 2) = ln 3
g(1.25) = ln(3.25) = ln(13/4) = ln 13 - ln 4
g(1.5) = ln(3.5) = ln(7/2) = ln 7 - ln 2
g(1.75) = ln(3.75) = ln(15/4) = ln 15 - ln 4
if you want undefined values look for x <= -2, as x > -2 is all defined

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