SOLUTION: please help me solve this equation;
log(base 6)3x + log(base 6)(x-1) = 3
Algebra.Com
Question 303095: please help me solve this equation;
log(base 6)3x + log(base 6)(x-1) = 3
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
x ={-7, 9}
But -7 is an extraneous solution, throw it out... leaving
x = 9
RELATED QUESTIONS
Please help me solve this equation: {{{ log base 4(x^2+6)=log base 4 (5x)... (answered by josgarithmetic)
Please help me solve this problem!
log base 4 x = log base 4 (x+6)=... (answered by Fombitz)
Please help me solve this equation: {{{log base a b^2*log base b... (answered by MathLover1)
please help me solve this equation
log base6(12) + log base 6(3) = (2/3)x
log... (answered by ewatrrr,rothauserc)
Please help me solve this equation: {{{ 2log base 3(x+4)-log base 3(9)=2 }}}
(answered by MathTherapy)
Please help me solve this equation: {{{ log base 3(7x) = log base 3(2x+.05)... (answered by josmiceli)
Please help:
I have solved this, but I'm unsure if it's right.
------------------
1/2... (answered by lwsshak3)
How to solve this equation:
log with base 2 (x) + log with base 6 (x) =... (answered by Nate)
Please help me solve this simultaneous equation:
log x base 3 = y = log (2x-1) base 9
(answered by Edwin McCravy)