SOLUTION: If log_2x=7, evaluate log_2 16x^2
Please any help is appreciated thank you
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Question 302789: If log_2x=7, evaluate log_2 16x^2
Please any help is appreciated thank you
Found 2 solutions by solver91311, london maths tutor:
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
\ =\ 7)
Since we know
\ =\ y)
means that
We can say
But we also know that
So
\ =\ \log_2\left(2^4\left(2^7\right)^2\right))
Which is to say:
)
Use the Power Rule
\ =\ 18)
because
\ =1)
John
Answer by london maths tutor(243) (Show Source): You can put this solution on YOUR website!
If log_2x=7, evaluate log_2 16x^2
Rewrite log2 (16x^2) as:
2[log2 (16x)]
=2(log2 16) + 2(log2 x) , log2 x = 7
=2(log2 2^4) + (2*7) , log2 2 = 1
=(2*4) + 14
= 8 + 14
= 22
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