SOLUTION: Show that
log[base 2]9 x log[base 3]8 = log[base 2]8 x log[base 3]9.
Thank you.
Algebra.Com
Question 30061: Show that
log[base 2]9 x log[base 3]8 = log[base 2]8 x log[base 3]9.
Thank you.
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
log[base 2]9 x log[base 3]8 = log[base 2]8 x log[base 3]9.
USING THE FORMULA
LOG (A) TO BASE B =LOG(A)/LOG(B)....TO ANY COMMON BASE WE GET
log[base 2]9 x log[base 3]8 = log[base 2]8 x log[base 3]9.
LHS={LOG(9)/LOG(2)}*{LOG(8)/LOG(3)}=LOG(9)*LOG(8)/{LOG(2)*LOG(3)}
RHS={LOG(8)/LOG(2)}*{LOG(9)/LOG(3)}=LOG(9)*LOG(8)/{LOG(2)*LOG(3)}
=LHS
RELATED QUESTIONS
4^log 3 base 9 + 9^log 4 base 2 =log^log 8.3 base... (answered by Alan3354)
log(base 3)x+log(base... (answered by scott8148)
Show that log base 9 (xy^2) = 1/2 log base 3 x + log base 3... (answered by josgarithmetic)
log base 2 (x-2)+log base 2(8-x)-log base... (answered by stanbon)
log(base)2 x+log(base)8 x+log(base)64 x=3 (then value... (answered by solver91311)
solve:
log 4 base 2 - log (x+3) base 2 = log 8 base... (answered by lwsshak3)
log(base 4)(x-9)=2
log(base 4)z + log(base... (answered by ewatrrr)
solve the equation.
log base b (X+3) = log base b (8) - log base b... (answered by lwsshak3)
Solve for x:
(A.) (5/2) log(base 4)4 = log(base 4)(2x-3)
(B.) Log(base 3)(x+2)-... (answered by stanbon)