SOLUTION: After tx years, the number of units of a product sold per year is given by Q=170*(.04^0.8t) After how many years will the number of units sold per year be 130?
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Question 29462: After tx years, the number of units of a product sold per year is given by Q=170*(.04^0.8t) After how many years will the number of units sold per year be 130?
I am lost here
tried
130=170*(.04^0.8t)
135/170 = (.04^0.8t)
.794117647059 = (.04^0.8t)
0.8t = log .04 .794117647059
0.8t=ln.794117647059/ln.04
t=.071616201169/.8
t=.089520251461
correct answer should be 6.18427107346822
Answer by venugopalramana(3286) (Show Source): You can put this solution on YOUR website!
SEE MY COMMENTS BELOW
After tx years,....WHAT IS TX?...YOU TOOK IT AS T YEARS...WHAT IS X?
the number of units of a product sold per year is given by Q=170*(.04^0.8t) After how many years will the number of units sold per year be 130?
I am lost here
tried
130=170*(.04^0.8t)
135/170 = (.04^0.8t)...ON THE LHS IT SHOULD BE 130/170..
.794117647059 = (.04^0.8t)...ON CORRECTION AS ABOVE = 0.764706..
0.8t = log .04 .794117647059..USE EITHER LOG TO DENOTE BASE 10...OR...LN TO DENOTE NATURAL LOGS TO BASE E
NO IT SHOULD BE
0.8T*LN(0.04)=LN(0.764706)
0.8T=LN (0.764706)/LN(0.04)=-0.26826/-3.21888=0.083341
T=0.083341/0.8=0.104176.......IS THE ANSWER...BUT IF AS YOU SAY THE ANSWER IS
6.184271...THEN YOU COPIED THE PROBLEM WRONGLY..LET US SEE IF IT IS
130=170*(.04^0.8)t...THEN THE ANSWER IS T=10.04 YEARS...SO CHECK BACK
0.8t=ln.794117647059/ln.04
t=.071616201169/.8
t=.089520251461
correct answer should be 6.18427107346822 ..
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