SOLUTION: Please solve: log8-log2x=-1

Question 293651: Please solve: log8-log2x=-1
Found 2 solutions by Alan3354, stanbon:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
log8-log2x=-1
log(2x) = log(8)+1 = log(80)
2x = 80
x = 40

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
log8-log2x=-1
---------------
log[8/(2x)] = -1
---
log[4/x] = -1
---
4/x = 10^-1
x/4 = 10
x = 40
=============
Cheers,
Stan H.
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