SOLUTION: Hi I couldnt figure out how to do this problem LOG6(x+3)+LOG6(x-2)=1

Question 289308: Hi I couldnt figure out how to do this problem
LOG6(x+3)+LOG6(x-2)=1
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Hi I couldnt figure out how to do this problem
LOG6(x+3)+LOG6(x-2)=1
------------
log6[(x+3)(x-2)] = 1
---
x^2+x-6 = 6^1
---------------
x^2+x-12 = 0
(x-4)(x+3) = 0
---
Acceptable solution:
x = 4
Note: x cannot be -3 because log(x-3)
would be log(0) which does not exist.
============
Cheers,
Stan H.
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