SOLUTION: Hi, I'm really not sure how to solve this problem.
log(2x)=log(x+70)
Each log has base 10. Any help would be really appreciated!
Algebra.Com
Question 288463: Hi, I'm really not sure how to solve this problem.
log(2x)=log(x+70)
Each log has base 10. Any help would be really appreciated!
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
log(2x)=log(x+70)
If the logs are equal, then
2x = x + 70
RELATED QUESTIONS
log(x) + log(2x) = 10
Im really confused on this question. Ive been trying this:... (answered by Earlsdon)
log(x) + log(2x) = 10
Im really confused on this question. Ive been trying this:... (answered by oscargut)
Hi! I need help in understanding this problem: Solve for x. Be sure to check your... (answered by josmiceli,Alan3354)
express x in terms of log 10 : 4^x-2 = 7^3x+1
I don't understand how I am suppose to... (answered by ewatrrr,josmiceli)
I am not to sure as to how to write "log y -(log 7 + log f)" as a single log. I really... (answered by Paul)
Solve and check
a)2logm + 3logm = 10
b)log(base 3)x^2 - log(base 3)2x = 2
c)log(base... (answered by solver91311)
How do you solve this for x ?
{{{ log ( 2 , 2x) }}} + {{{ log (2 , x) }}} = 5
I'm... (answered by richard1234)
Hi, I need help in solving this logarith problem:-
Solve the simultaneous equations
(answered by Earlsdon)
solve each:
(Can you please provide steps. i would really appreciate it. It would help (answered by Tatiana_Stebko)