SOLUTION: log2(5-x)+log2(5+x)=4

Question 286068: log2(5-x)+log2(5+x)=4
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Solve for x:
Apply the "product rule" for logarithms:
Simplify the left side.
Recall the definition of the logarithm:
"The logarithm of a number (or an expression) is the power to which the base must be raised to equal that number (or expression)"
Rewrite the above equation accordingly:
Simplify.
Rearrange into a standard quadratic equation.
Factor the left side.
Apply the "zero product rule"
or therefore:
or
RELATED QUESTIONS
log2 (x+1) + log2 (x-5) =... (answered by solver91311)

log2^(x+4)- log2^(x-4)=... (answered by Nate)

log2(x - 2) + 5 = 8 - log2... (answered by mukhopadhyay)

log2(x - 2) + 5 = 8 - log2... (answered by Nate)

log2(x - 2) + 5 = 8 - log2... (answered by jim_thompson5910)

log2(3x-2)-log2(x-5)=4 (answered by robertb)

log2^x = log2^5... (answered by themathtutor2009)

log2... (answered by jsmallt9)

Log2... (answered by MathLover1,MathTherapy)