SOLUTION: log3(3x)=log3x+log3(4-x)
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Question 285871: log3(3x)=log3x+log3(4-x)
Answer by user_dude2008(1862) (Show Source): You can put this solution on YOUR website!
log3(3x)=log3x+log3(4-x)
log3(3x)=log3[x(4-x)]
3x=x(4-x)
3x=4x-x^2
x^2-4x+3x=0
x^2-x=0
x(x-1)=0
x=0 or x-1=0
x=0 or x=1
Answer: only solution is x=1
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