SOLUTION: Express as a sum of logarithms.
log[4](64 ∙ 256)
Algebra.Com
Question 283763: Express as a sum of logarithms.
log[4](64 ∙ 256)
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
In algebgra.com language, the answer is:
log(4,(64*256)) = log(4,64) + log(4,256)
After being put through the algebra.com formula generator, the answer looks like this:
In english, the answer is:
log(64*256) to the base of 4 is equal to log(64) to the base of 4 plus log(256) to the base of 4.
In your language, the answer is:
log[4](64*256) = log[4](64) + log[4](256).
This is because, in general:
log(b,a*c) = log(b,a) + log(b,c)
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