# SOLUTION: What is the value of x? 0.5 ln (110-x)+0.5 ln (100-x) = 4.26 0.8 ln (200-x) + 0.2 ln (100-x) = 4.56

Algebra ->  Algebra  -> Logarithm Solvers, Trainers and Word Problems -> SOLUTION: What is the value of x? 0.5 ln (110-x)+0.5 ln (100-x) = 4.26 0.8 ln (200-x) + 0.2 ln (100-x) = 4.56      Log On

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 Algebra: Logarithm Solvers Lessons Answers archive Quiz In Depth

 Question 282424: What is the value of x? 0.5 ln (110-x)+0.5 ln (100-x) = 4.26 0.8 ln (200-x) + 0.2 ln (100-x) = 4.56Answer by dabanfield(803)   (Show Source): You can put this solution on YOUR website!1.) 0.5 ln (110-x)+0.5 ln (100-x) = 4.26 2.) 0.8 ln (200-x) + 0.2 ln (100-x) = 4.56 1.) .5 ln(110-x) + .5 ln(100-x) = 4.26 .5*(ln(110-x)+ ln(100-x)) = 4.26 ln(110-x) + ln(100-x) = 4.26/.5 Using the law ln a + ln b = ln (a+b): ln((110-x)*(100-x)) = 8.52 By definition of ln we have: (110-x)*(100-x) = e^8.52 Solve the above for x using the quadratic formula. 2.) 0.8 ln (200-x) + 0.2 ln (100-x) = 4.56 Are you sure the equation above is written correctly?