SOLUTION: How do you solve this equation?
2lnX-ln3=2
Algebra.Com
Question 282272: How do you solve this equation?
2lnX-ln3=2
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Solve by applying log rules:
2lnX-ln3=2
lnX^2-ln3=2
ln(X^2/3)=2
X^2/3 = e^2
X^2 = 3e^2
X = sqrt(3e^2)
X = 4.71
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