SOLUTION: please help - not sure how to solve when I end up with log fractions?
ln(x)- ln(x+1) = ln(x+3) - ln(x+5)
ln x/x+1 = ln x+3/x+5 ?????
Thanks
JP
Algebra.Com
Question 27481: please help - not sure how to solve when I end up with log fractions?
ln(x)- ln(x+1) = ln(x+3) - ln(x+5)
ln x/x+1 = ln x+3/x+5 ?????
Thanks
JP
Answer by longjonsilver(2297) (Show Source): You can put this solution on YOUR website!
ln(x)- ln(x+1) = ln(x+3) - ln(x+5)
ln = ln
and now we get rid of the log. How do we get rid of anything in maths? we do the opposite... so opposite of log is "raise to power". So, doing that, the "raising to the power" and the "log" cancel each other, so we are left with
5x = 4x + 3
x = 3
jon.
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