SOLUTION: how to change this to base 4? log64 512

Algebra.Com
Question 270229: how to change this to base 4?
log64 512

Answer by CharlesG2(834)   (Show Source): You can put this solution on YOUR website!
how to change this to base 4?
log64 512
log64 512 = x (set it equal to x)
base b = 64
set y = 512
b^x = y --> 64^x = 512 --> 64 * 64^(1/2) = 512 --> x=3/2
logb (x) = logd (x) / logd (b) (d here is your new base)
4^0 = 1, 4^1 = 4, 4*4 = 16, 16*4 = 64, 64*4 = 256 , 256*2 = 512, 256 * 4 = 1024
log64 (512) = log4 (512) / log4 (64)
512/64 = 4^(4.5)/4^3 = 4*4*4*4*4^(1/2) / 4*4*4 = 4*4^(1/2) = 4^(3/2) = 8
log64 (512) = log4 (8) = 3/2
or 64^(3/2) = 512 and 4^(3/2) = 8






RELATED QUESTIONS

prove that log64 to base 3 divided by log8 to base 9 =... (answered by Alan3354)
(LOG64^600)/(LOG4) This is what I have done so far. I don't know how to write it on here (answered by Alan3354)
log64/log4, log64/log8, log64/log32 Decribe how to obtain the third answer in each row... (answered by stanbon)
Describe how to obtain the third answer in each row from the first two questions? a)... (answered by Earlsdon)
how to change base in logarithm (answered by Shin123)
How to find log (5,512) ? i.e., log 512 to the base 5.. log 2 base 10 =0.3010 and log 3... (answered by jsmallt9)
Evaluate log 512 to the base 2√ 2... (answered by lwsshak3)
change 74(in base 10)to base... (answered by stanbon)
how to evaluate... (answered by Fombitz)