SOLUTION: For the equation y=ln(x+2), could you state the equation of the line asymptotic to the graph (if any)? Thanks

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Question 270120: For the equation y=ln(x+2), could you state the equation of the line asymptotic to the graph (if any)? Thanks
Answer by jsmallt9(3758) About Me  (Show Source):
You can put this solution on YOUR website!
y = ln(x+2)

For a function like this, where y equals some logarithm, then there will be a vertical asymptote at the "edge" of the domain.

So we will start by finding the domain of this function. The arguments of all logarithms, regardless of the base, must be positive. So the domain of this function are the values that make (x+2) positive. In other "words":
x%2B2+%3E+0
Solving this we find that
x+%3E+-2
This is the domain of this function.

To find the vertical asymptote, just change this to an equation:
x+=+-2
This is the equation of the vertical asymptote for y = ln(x+2).