SOLUTION: Find the integral values of x, y, and z that satisfy all of the following equations: z^x = y^2x 2^z = (2)(4^x) x+y+z=16 I'd appreciate the help! P.S. Thanks to longjonsilver

Question 26360: Find the integral values of x, y, and z that satisfy all of the following equations:
z^x = y^2x
2^z = (2)(4^x)
x+y+z=16
I'd appreciate the help!
P.S. Thanks to longjonsilver(1462)for recognizing the problem's mistake.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
z^x=(y^2)^x implies that z=y^2 or y=sqrt(z)
2^z=2^(3x) implies that z=3x
Therefore y=sqrt(3x)
But x+y+z=16
So, x+sqrt(3x)+3x=16
This can be solved for "x".
Using that you can find values for y and z.
Cheers,
Stan H.
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