SOLUTION: PLEASE HELP!!! If (log base 3 of x)(log base x of 2x)(log base 2x of y) = log base x of x2, find the value of y. Thanks in advance.

Question 26295: PLEASE HELP!!!
If (log base 3 of x)(log base x of 2x)(log base 2x of y) = log base x of x2, find the value of y.
Thanks in advance.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
You need to know the law log base b of a = [log a}/[log b]
So, rewriting your problem you get:
[log x]/[log 3]/[log x]/[log 2x]= [log x^2]/[log x]
Denominators cancel with numerators to give the following:
[log y]/[log 3]= [2log x]/[log x[
Rewrite as:
log base 3 of y = 2
Therefore y=3^2=9
y=9
Cheers,
stan H.
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