SOLUTION: log(3x)= log 5 + log(x-2)
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log(3x)= log 5 + log(x-2)
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Here is the question
step 1 subtract log(x-2) to get
step 2 - rewrite using rules of logs as
step 3 - eliminate logs to get
step 4 - cross multiply to get
solve for x and we get
x = 5