SOLUTION: log(4-x)=log(x+8)+log(2x+13)
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Question 254433: log(4-x)=log(x+8)+log(2x+13)
Answer by palanisamy(496) (Show Source): You can put this solution on YOUR website!
The given equation is
log(4-x)=log(x+8)+log(2x+13)
log(4-x) = log(x+8)(2x+13)
Taking anti-log,
(4-x) = (x+8)(2x+13)
4-x = 2x^2+13x+16x+104
0 = 2x^2+29x+104+x-4
0 = 2x^2+30x+100
Dividing by 2,we get
x^2+15x+50 = 0
(x+5)(x+10) = 0
x = -5 or -10
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