SOLUTION: LogM+LogY=(2/3)LogX Solve for M

Question 253955: LogM+LogY=(2/3)LogX
Solve for M
Found 2 solutions by stanbon, palanisamy:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
LogM+LogY=(2/3)LogX
Solve for M
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L(MY) = Log(X^(2/3)
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MY = X^(2/3)
M = [X^(2/3)]/Y
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Cheers,
Stan H.
Answer by palanisamy(496) (Show Source): You can put this solution on YOUR website!
Given, LogM+LogY=(2/3)LogX
LogM = Log[X^(2/3)]-LogY
LogM = Log[x^(2/3)/Y]
Taking anti-log,
We get M = x^(2/3)/Y
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