SOLUTION: If a=log(base7)(11-6√2) and b=log(base7)(45+29√2), find 3a+2b in the simplest form.

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Question 253720: If a=log(base7)(11-6√2) and b=log(base7)(45+29√2), find 3a+2b in the simplest form.
Answer by Theo(13342)   (Show Source): You can put this solution on YOUR website!
If and , find 3a+2b in the simplest form.

if and only if

if and only if

take log of both sides of first equation to get:

becomes:



this becomes:



divide both sides by log((7)) to get:

*************

take log of both sides of second equation to get:

becomes:



this becomes:



divide both sides by log((7)) to get:





since the denominator is the same, we get:



I don't think you can simplify it any further, but you can solve it using the LOG function of your calculator.

equation becomes:



this becomes:



I confirmed the answer is correct by using the logarithm base conversion formula to convert base 7 logarithm to a base 10 logarithm.

that conversion formula is:



you could also have solved this problem directly by using the base conversion formula.

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