SOLUTION: All logs are base 12 Logx=.5log9+1/3log27 I got 49.5, I'm just wondering if it's right. THANKS!

Algebra ->  Logarithm Solvers, Trainers and Word Problems -> SOLUTION: All logs are base 12 Logx=.5log9+1/3log27 I got 49.5, I'm just wondering if it's right. THANKS!      Log On


   

Question 253368: All logs are base 12
Logx=.5log9+1/3log27
I got 49.5, I'm just wondering if it's right. THANKS!
Found 2 solutions by nerdybill, edjones:
Answer by nerdybill(7384) About Me  (Show Source):
Answer by edjones(8007) About Me  (Show Source):
You can put this solution on YOUR website!
All logs are base 12
log(x)=.5log(9)+1/3log(27)
log(x)=log(3)+log(3) [log(sqrt of 9) + log(cube root of 27)]
log(x)=log(9)
x=9 This answer is the same no matter what base is used and you don't have to convert any logs to get the answer!
.
Ed