SOLUTION: how do I solve ln(15y-10)-ln(1-y)=ln(x-2)+ln(5-x)

Algebra.Com
Question 25276: how do I solve
ln(15y-10)-ln(1-y)=ln(x-2)+ln(5-x)

Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
ln[(15y-10)/(1-y)] = ln[(x-2)(5-x)]
Take the anti-ln of both sides to get:
[(15y-10)/(1-y)] = [(x-2)(5-x)]
This cannot be further simplified and
only allows for "y" to be solved it terms
of "x".
Cheers,
stan H.

RELATED QUESTIONS

how do you solve ln(x)... (answered by Fombitz)
how do i solve the equation? ln (x-10)-ln (x+7) = ln (x-4) - ln... (answered by Alan3354)
Solve: log base 4 (X) + Log base 8 (x) = 1 ln X/ln 4 + ln X/ln 8=1 2 ln X/2 ln 4 + ln... (answered by Fombitz)
How do I solve :... (answered by reviewermath)
ln 40 + 2 ln .5 + ln... (answered by edjones)
Solve... (answered by stanbon)
how do i solve for x?... (answered by longjonsilver)
How do I solve these problems? 1. ln(5 - x) + ln(-3 - x) = ln(1 - 8x) 2.... (answered by josgarithmetic,MathTherapy)
ln (ln x) =... (answered by Fombitz)