SOLUTION: I was told to Repost this question Evaluate the exponential equation for three positive values of x, three negative values of x, and at x=0. Show your work. Use the resulting orde

Question 251372: I was told to Repost this question
Evaluate the exponential equation for three positive values of x, three negative values of x, and at x=0. Show your work. Use the resulting ordered pairs to plot the graph; submit the graph via the Dropbox. State the equation of the line asymptotic to the graph (if any).
y=3^x-4+1
The exponent if I understand question is x-4

Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
So now choose three positive value for x and three negative values for x and x=0
and solve for y
x=6 :y=3^(6-4)+1:y=3^(2)+1=9+1
x=5 :y=3^(5-4)+1=y=3^1+1=3+1
x=4 :y=3^(4-4)+1:y=3^0+1=1+1
x=-1:y=3(-1-4)+1:y=3^(-5)+1:y=1/3^5+1
x=-2:y=3(-2-4)+1:y=3^(-6)+1:y=1/3^6+1
x=-3:y=3(-3-4)+1:y=3^(-7)+1::y=1/3^7+1
x=0: y=3^(-4)+1:y=1/3^4+1
finish calculating and
plot those values

RELATED QUESTIONS
evaluate the exponential equation for three positive values of x, three negative values... (answered by drk,JBarnum)

Evaluate the exponential equation for three positive values of x, three negative values... (answered by RAY100)

1. Evaluate the exponential equation for three positive values of x, three negative... (answered by richwmiller)

Evaluate the exponential equation for three positive values of x, three negative values... (answered by Fombitz)

Can someone help me figure this problem out, I am so lost....Evaluate the exponential... (answered by solver91311)

Evaluate the exponential function for three positive values of x, three negative values... (answered by stanbon)

Evaluate the exponential equation for three positive values of x, three negative values... (answered by richwmiller)

y = -3^x Evaluate the exponential equation for three positive values of x, three... (answered by jim_thompson5910)

Can someone please help me with this problem? please. Evaluate the exponential equation... (answered by Alan3354,stanbon)