SOLUTION: solve for x:
x^3/2(to the 3 over 2) - 27=0
___________ __
4^x=79
___________ __
9^x+2=27^x
___________ ___________ ___________ ___________ ______
write the logarit
Algebra.Com
Question 251057: solve for x:
x^3/2(to the 3 over 2) - 27=0
______________
4^x=79
______________
9^x+2=27^x
______________________________________________________
write the logarithmc equations for the following
A = s^2 /4(s to the 2 over 4) sqrt3
________________
R = sqrt3V/mH (R equals the squareroot of 3V over mH)
Found 2 solutions by richwmiller, JimboP1977:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
You have too many questions qrouped together.
Resubmit individually
x^3/2 - 27=0
x^(2/3)=27
raise both sides to 2/3
x^(3/2*2/3)=27^(2/3)
x^1=27^(2/3)
27(2/3)=
27(1/3)=3
then 3^2=9
Answer by JimboP1977(311) (Show Source): You can put this solution on YOUR website!
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4dp.
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lets get the bases to be 3.
Now you try the rest...
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