SOLUTION: Maria is twice as old as Jasmine. Six years ago, Maria was three times as old as Jasmine was then. Find the age of each girl.
Algebra.Com
Question 249542: Maria is twice as old as Jasmine. Six years ago, Maria was three times as old as Jasmine was then. Find the age of each girl.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Maria is twice as old as Jasmine. Six years ago, Maria was three times as old as Jasmine was then. Find the age of each girl.
---------------
NOW DATA:
Let Maria by "m"
Let Jasmine b "j"
--------------------------
Equations:
m = 2j
(m-6) = 3(j-6)
-----------------
Substitute for "m" and solve for "j":
(2j-6) = 3(j-6)
2j-6 = 3j-18
j = 12 (Jasmine's age now)
Since m = 2j, m = 24 (Maria's age now)
=======================================
Cheers,
Stan H.
------
RELATED QUESTIONS
The sum of the age of Jasmine and her mother is 100. 30 years ago, Jasmine’s mother was (answered by ikleyn)
Maria is now four times as old as Kate. Four years ago, Maria was six times as old as... (answered by hheuler)
Jasmine is three rimes as old as Jasper. In 12 years, Jasmine will be twice as old as... (answered by mananth)
Mandy is twice as old as Jessica. Three years ago Mandy was three times as old as Jessica (answered by fractalier)
Mary is twice as old as Judy. Six years ago Mary was three times as old as Judy. Find the (answered by ankor@dixie-net.com)
ten years ago, jane was four times as old as maria now she is only twice as old as maria. (answered by josmiceli)
the sum of the ages of jasmine and her mother is 100. thir years ago jasmine's mother was (answered by solver91311,colin514,JBarnum)
Bob, Maria, and Shoshana all have birthdays on the same day. Bobs present age is two... (answered by stanbon,MathTherapy)
Maria is now twice as old as Lenlen. Five years ago she was three times as old as Lenlen. (answered by josgarithmetic,ikleyn)