SOLUTION: Express as a difference of logarithms. log4 1 - log4 2 log8 1 + log8 2 log8 1 - log8 2 log8 2 - log8 1

Algebra.Com
Question 247787: Express as a difference of logarithms.


log4 1 - log4 2
log8 1 + log8 2
log8 1 - log8 2
log8 2 - log8 1

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


I assume that you meant to show a problem and four possible answers -- but you didn't show the problem. Well, answer 2 is out because that is not a difference of logs, it is the sum of logs. Your problem must be the log to some base, hopefully it is either 4 or 8, of a fraction. If the base is 4, then the first answer is correct. If the base is 8 and the numerator of your fraction is 1, then the third answer is correct. If the base is 8 and the numerator is 2 (or if you don't have a fraction and the argument is just 2), the fourth answer is correct.


John


RELATED QUESTIONS

Log8(2)=1/3 (answered by stanbon)
log8^x/2=log8^x/log8^2 (answered by Alan3354)
expree as a difference of lagarithms log8... (answered by jim_thompson5910)
solve for x... (answered by nerdybill)
Hi, Can you help me with this math problem? 12.) Rewrite the expression as a... (answered by solver91311)
log8 (answered by stanbon,lynnlo)
log8-logx-log(x-2)=-1 (answered by LinnW)
log8 (x+1) + log8 (x+3)=log8... (answered by ankor@dixie-net.com)
log8 x^2 = (log8... (answered by josmiceli)