SOLUTION: solve. log(x^2+3)=log(x+6)

Algebra.Com
Question 246241: solve.
log(x^2+3)=log(x+6)

Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
log(x^2+3)=log(x+6)
10^log(x^2+3)=10^log(x+6)
x^2+3=x+6
x^2-x-3=0
x=(1+sqrt(13))/2, x=(1-sqrt(13))/2
.
Ed
.
Solved by pluggable solver: SOLVE quadratic equation with variable
Quadratic equation (in our case ) has the following solutons:



For these solutions to exist, the discriminant should not be a negative number.

First, we need to compute the discriminant : .

Discriminant d=13 is greater than zero. That means that there are two solutions: .




Quadratic expression can be factored:

Again, the answer is: 2.30277563773199, -1.30277563773199. Here's your graph:

RELATED QUESTIONS

Solve: Log x + log (x+6) =... (answered by jim_thompson5910)
{{{log(2,x)+log(6,x)=3}}} (answered by lwsshak3)
solve: (log(5x-6))/log(x) = 2 (answered by dabanfield)
Solve for x: log(x - 3) = (log x - log... (answered by nerdybill)
Solve for x: log(x-2)+ log x = log... (answered by edjones)
solve log 4x = log(x+3)+log 2 for... (answered by ewatrrr)
log(X+3)-log X=log... (answered by Fombitz)
Solve the equation {{{log(16,(x))+log(8,(x))+log(4,(x))+log(2,(x))=6}}} (answered by jim_thompson5910)
How do I work log(x-1)-log(x+6)=log(x-2)-log(x+3) (answered by josgarithmetic)