SOLUTION: solve the equation.
log3x=log2+log(x-4)
Algebra.Com
Question 245685: solve the equation.
log3x=log2+log(x-4)
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Applying "log rules":
log3x=log2+log(x-4)
log3x=log2(x-4)
3x=2(x-4)
3x=2x-8
x = -8
RELATED QUESTIONS
Log2(log3x)=4
Solve for... (answered by lwsshak3)
solve logarithmic equation... (answered by rfadrogane)
Solve the equation and please explain step by step
log(3+x)-log(x-4)=log2... (answered by fractalier,MathLover1)
log3x=log4+log(x-1)
solve this logarithmic... (answered by Susan-math)
solve equation and express solution in exact form... (answered by Alan3354)
PLEASE HELP
Solve this equation:
log (4x-4)* log (x+2) =... (answered by nerdybill)
Solve the equation {{{log(16,(x))+log(8,(x))+log(4,(x))+log(2,(x))=6}}} (answered by jim_thompson5910)
Solve the equation:... (answered by jsmallt9)
log(x+22)-log2=log(5x+2)
solve the logarithmic... (answered by Kg2003)