SOLUTION: just wanna see how these problems are worked out.
1.logc 3sq root y^3 z^2/x^4. sorry could make the sq root sign.
2.1/2loga-log2
3.ln2x-3(lnx-lny)
Algebra.Com
Question 242767: just wanna see how these problems are worked out.
1.logc 3sq root y^3 z^2/x^4. sorry could make the sq root sign.
2.1/2loga-log2
3.ln2x-3(lnx-lny)
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
Sorry, but #1 is confusing. What part goes inside of the radical?
The way to represent square root with the keyboard is: sqrt(x) which means 
. Everything you put inside of the parentheses is under the radical. The way you wrote your problem, I can't tell if you meant:
)
or
)
or
)
And you don't actually say what it is you want to do with this logarithm.
#2. Always put your log arguments in parentheses. I presume you meant:
\ \ \log(2))
I can only presume, because you didn't take the time to say, that you want to express this as a single logarithm.
First:
 = n\log_b(x))
So
\ -\ \log(2)\ =\ \log\left(a^{\frac{1}{2}}\right)\ -\ \log(2)\ =\ \log\left(\sqrt{a}\right)\ -\ \log(2))
The difference of the logs is the log of the quotient, that is:
 - \log_b(y) = log_b\left(\frac{x}{y}\right))
So:
 - \log(2) = \log\left(\frac{\sqrt{a}}{2}\right))
Use the same rules for solving 3 as I showed you for 2 with the addition of the rule:
The sum of the logs is the log of the product:
 + \log_b(y) = \log_b(xy))
John
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