SOLUTION: solve for x log_2(3-x)+log_2(1-2x)=5

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Question 242396: solve for x
log_2(3-x)+log_2(1-2x)=5
Answer by Fombitz(32388) About Me  (Show Source):
You can put this solution on YOUR website!
log%282%2C%283-x%29%29%2Blog%282%2C%281-2x%29%29=5
log%282%2C%28%283-x%29%281-2x%29%29%29=5
%283-x%29%281-2x%29=2%5E5
3-6x-x%2B2x%5E2=32
2x%5E2-7x-29=0
Use the quadratic formula,
x+=+%28-%28-7%29+%2B-+sqrt%28+%28-7%29%5E2-4%2A%282%29%2A%28-29%29+%29%29%2F%282%2A2%29+
x+=+%287+%2B-+sqrt%28+281+%29%29%2F%284%29+
Two solutions:
x=5.941
x=-2.441
Check the solutions,
log%282%2C%283-x%29%29%2Blog%282%2C%281-2x%29%29=5
log%282%2C%28-2.941%29%29%2Blog%282%2C%28-10.882%29%29=5
Negative arguments for logs are not allowed.
x=5.941 is not a solution.
log%282%2C%283-x%29%29%2Blog%282%2C%281-2x%29%29=5
log%282%2C%285.441%29%29%2Blog%282%2C%285.882%29%29=5
2.4439%2B2.5563=5
4.9999=5
Close enough.
x=-2.441