SOLUTION: so im not sure if i need to go another step when they say "write the following expression as a single logarithm"
Equation: 1/4log(x)-slog(y)+7/10log(z)
My anzwer: log(x^4 squar
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Question 241166: so im not sure if i need to go another step when they say "write the following expression as a single logarithm"
Equation: 1/4log(x)-slog(y)+7/10log(z)
My anzwer: log(x^4 square root (z^7))/square root (y)
Do i need to go another step?
Found 2 solutions by Alan3354, solver91311:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
1/4log(x)-slog(y)+7/10log(z)
My anzwer: log(x^4 square root (z^7))/square root (y)
------------
1/4log(x)-slog(y)+7/10log(z)
= log(x^(1/4)) - log(y^s) + log(z^(7/10))
=
-----------
I don't see how you got square roots. Is the 's' a square root?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
In the first place, how did you get from
)
to
)
when using
\ =\ \log\left(x^n\right))
?
It should have been
\ =\ \log\left(\sqrt[4]{x}\right))
What does "slog" mean? Were you trying to represent )
?
Also:
\ =\ \log\left(z^{\frac{7}{10}}\right)\ =\ \log\left(\sqrt[10]{z^7}\right))
John
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