SOLUTION: what is x if: logx(16)=-2 I have x^-2=16 x^-2^-1=16^-1 x^2=1/16 2 squareroot 1/16

Question 240520: what is x if: logx(16)=-2
I have x^-2=16
x^-2^-1=16^-1
x^2=1/16
2 squareroot 1/16
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!

All of this...
I have

(Rejecting -sqrt(1/16) because x is the base of a logarithm and we don't have logarithms with negative bases.)
... is great. But you should simplify your answer:

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