SOLUTION: Rewrite as a sum and/or difference of multiples of logarithms: ln((3x^2)/square root 2x+1))....my answer was 2ln(3x) + 1/2ln(2x+1) is this correct?

Algebra.Com
Question 240493: Rewrite as a sum and/or difference of multiples of logarithms:
ln((3x^2)/square root 2x+1))....my answer was 2ln(3x) + 1/2ln(2x+1) is this correct?

Found 2 solutions by jim_thompson5910, jsmallt9:
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
Start with the given expression.


Break up the log using the identity


Break up the first log using the identity


Convert to rational exponent notation.


Pull down the exponents using the identity


So

Answer by jsmallt9(3759)   (Show Source): You can put this solution on YOUR website!
You have unbalanced parentheses in your problem so I have to check. Is this the original logarithm?

If yes, keep reading. If not, then please repost your problem with properly balanced parentheses.

Your answer, , is pretty close. One error is that it should be a difference instead of the sum because of the division in the original log:

This may meet the requirements of the problem. But it is possible to use the property, , on the first log giving:

I don't know if this last expression would be preferred over .

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